free math problem solver with steps

We should know how to use the facility of Free Math Problem Solver with Steps, which guides us how to follow the steps for solving the math problems online. These problems can be based on different topics. In general a child of grade 6 has the problems based on profit and loss, percentage, simple interest and the compound interest and how to solve the mathematical expressions having more than one operation.  To solve the problems of mathematical expression, we have certain set of rules to be followed, which tells us which mathematical operation is to be performed and then which operator needs to be followed.  This is called the hierarchy of operations to be performed. In the hierarchy of operations, we will follow the rules of BODMAS, which means the following:
 B stands for Bracket
O – stands for Of operation
D- stands for division of terms
M- stands for  Multiplication of terms
A – stands for the  Addition Operation
S- Stands for the Subtraction operation.
 Thus we observe that if we follow this hierarchy of operation, it is clear that every time anyone will perform the operation of solving the expression, we say that the   result for the given expression will remain same. Thus  when the result for the expression is to be calculated, we ensure that first we will open the brackets and for this the operations in the brackets are to be  performed, followed by  “ of “ operation, then we perform division, then multiplication , then addition followed by subtraction operation.
 In order to learn how to use online Calculating Confidence Intervals, we must be aware of the free online features available on the above topics.  To know about the curriculum and the subject available in Ap State Board Of Secondary Education, a child should be able to understand the subject online.
In the next session we will discuss about De Morgans law and if anyone want to know about Lines of Symmetry Shapes then they can refer Internet and text books for understanding it more precisely.

online tutors homework help

To solve ,Algebraic Equations we will separate the constants and the variables and thus get the value of the variable in the given equation. In order to get the value of the variable, we need to  move the constant  on one side and the variables are moved to another side of the equation. Always remember that while we solve the equation, and we need to move a term from lone side of the equation to another, then the positive term will change to a negative term and a negative term will change to a positive term.  In the same way, we change the sign of multiplication to division and the relation of division changes to multiplication, thus the algebraic equations are solved and we get the value of the variable of the equation. To check that the value of the variable calculated is correct or not, we will place the value of the variable in the given equation and we find that the value satisfies the equation.
We must remember that a linear algebraic equation can have only one value or solution to the given equation. On the another hand a quadratic equation can have  at most two values of the variables,  and if the equation is a cubic equation, then we say that the variable can have  at the most three values. So we say that quadratic equations can have no solution, one solution or at the most two solutions. In the same way a cubic equation can have either 0 or 1, or 2 or 3 values of the variables.We have different ways to solve the equation and to get the solutions for the given linear equations.
We always have online tutors homework help to know and to learn more about Tamilnadu Board Logic Sample Papers.
In the next session we will discuss about free math problem solver with steps
and if anyone want to know about Axis of Symmetry then they can refer Internet and text books for understanding it more precisely.

Distributive law and prepositions

Hello students, Previously we have discussed about subtracting integers worksheet and In today's session we are going to discuss about Distributive law and prepositions which comes under state board of maharashtra syllabus, In mathematics we study many laws like distributive, idempotent, complement, and associative laws. In this session, we are going to discuss the Distributive Law and Prepositions which are generally used in various fields of mathematics. These laws come in Boolean Algebra laws and are basic laws of the algebra too for showing logical equivalence (i.e. a kind of relationship between the two expressions).
The Common Distributive Law can be stated for all real number x, y and z as:
x ( y + z ) = x y + x z
The statements x ( y + z ) define the order in which we will add the y and z values then multiply x by the result.
The statements x y + x z define the order in which we multiply x and y, then multiply x and z and then add the multiplied results.(Know more about Distributive law in broad manner, here,)
Just take an example to understand it: -
x = 4, y = 5, z = 6
The distributive law is x ( y + z ) = x y + x z
Solution: - 4 (5 + 6 ) = 4 . 5 + 4 . 6
Note :- ( . ) dot operator specifies the multiplication.
4 ( 11 ) = 20 + 24
44 = 44
The Distributive law in terms of logical equivalence (explained with the help of prepositions which can be defined as symbols that show mathematical relationship between two statements) is:-
P ∧ ( Q v R ) = ( P ∧ Q ) v ( P ∧ R )
P v ( Q ∧ R ) = ( P v Q ) ∧ ( P v R )
Where preposition ∧ is used for AND, and v for OR operation.
So these laws describes the two different ways but both ways produce same results.
In the next session we are going to discuss online tutors homework help
and if anyone want to know about Congruence and Similarity then they can refer  Internet and text books for understanding it more precisely.

De Morgans law

Previously we have discussed about multiplying polynomials worksheet and In today's session we are going to discuss about Law of De Morgans which is a part of maharashtra higher secondary board syllabus, It interchanges an equation form to its negation form. Here negation means its opposite form. The law provides some rules that are known as transformation rules because it transforms an equation form to its negation form. By De Morgans law, we can relate conjuction and disjunction in terms of each other.
In simple english, Applying negation on the conjuction form of an equation gives us the disjunction of its negations. In other words, Applying negation on a disjunction form of an equation gives us the conjuction of its negations.

In logical language form,De Morgans law can be expressed as,
( A á´§ B ) ' = ( A ) ' á´  ( B )'
( A á´  B ) ' = ( A ) ' á´§ ( B )'

here ' stands for the negation of the expression.
á´§ stands for the conjuction of two expressions.
á´  stands for disjunction of two expressions.
= sign stands for equality,i.e we can replace one form to another form
The law has many forms.i.e, we can define the law in many ways.

This law has the same meaning in set (Data Set Example) theory.

The substitution form of this law is as follows ,

X . Y = ( X' + Y ' )'
X + Y = ( X' . Y ')'
. stands for conjuction and + stand for Disjunction .
' stand for the negation .

This law also holds for the functional forms as,
if we have two functional operator X and Y, then

X AND Y = NOT ( ( NOT X ) OR ( NOT B )
X OR B = NOT ( ( NOT X ) AND ( NOT Y ) )

AND operator stands for the conjuction and OR operator stands for the disjunction .(Know more about De Morgans law in broad manner, here,)
NOT operator stands for the negation.
In the next session we are going to discuss Distributive law and prepositions
and Read more maths topics of different grades such as Geometric Shape Attributes in the upcoming sessions here.

Boolean Laws

Hi friends, Previously we have discussed about slope worksheets and today we are going to learn about Boolean Laws, one of the most interesting and a bit complicated topic of mathematical world named as Boolean Algebra that comes into maharashtra education board. To solve Boolean Algebra problems what we need to do is hard work and a daily little practice. Boolean laws and theorems are also needed to understand before starting to solve boolean algebra.
Boolean Algebra :-It was developed by George Boole in year 1840 , it represents logical calculus of truth values and algebra of real numbers with operations like ab , a+b ,
Boolean algebra (or Boolean logic) is a logical calculus of truth value, developed by George Boole in the 1840s. It resembles the algebra of real numbers, but with the numeric operations of multiplication xy, addition x + y, and negation −x replaced by the respective logical operations, (Know more about Boolean Laws in broad manner, here,)
It is algebra of two algebra values where one can be either true or false
Boolean Laws:

Identity for Single Variable
Operations with 1and 0: 1. A+ 0 = A (identity) 3. A + 1 = 1 (null element)	2. A.1 = A 4. A.0 = 0
Idempotency theorem: 5. Y + Y = Y	6. Y.Y = Y
Complementarity: 7. X + X’ = 1	8. X.X’ = 0
Involution theorem: 9. (Y’)’ = Y
Identities for multiple variables
Commutative law:  10. A + B = B + A	11. A.B = B.A
Associative law: 12. (X + Y) + Z = X + (Y + Z)      = X + Y + Z	13. (XY)Z = X(YZ)        = XYZ
Distributive law: 14. a(b + c) = ab + ac	15. a + (bc) = (a + b)(a + c) Example :  (A+B)(AC+AC)+AB+B Solution :(A+B)A(C+C)+AB+B (A+B)A+AB+B A((A+B)+B)+B A(A+B)+B AA+AB+B A+(A+T)B A+B

Conjunction disjunction and Complement are the three basic operations which we can perform on Boolean values.
In The Next Topic We Are Going To Discuss Boolean Laws and if anyone want to know about Constructing geometry shapes then they can refer to Internet and text books for understanding it more precisely.

Bi Conditional Statements

Previously we have discussed about number line worksheets and In today's session we are going to discuss about Bi conditional statements which is a part of maharashtra state board of secondary and higher secondary education ac provides you excellent college algebra help. They are used to write the definitions in the geometry. In geometry definition is defined as statements for defining the mathematical objects and these statements are written in the form of bi conditional statements. For creating the bi conditional statements we combine the conditional statements and also converse it .
Bi Conditional statements are the statements that are written in the form of “ x if and only if y; “ that have the meaning that if x is true then y is also true. Bi conditional statements “ x if and only if y “ is also write as “ x iff y “ or x < - > y .
When both the conditional statement and its converse are true then its bi conditional statement is also true . When both the conditional and its converse are false then the bi conditional statement is also false .
Bi conditional statement examples:
If there are two statements x : A polygon is a triangle .
Y : A polygon has absolutely 3 sides .
So the problem based on these statements is determine the truth values of these statements :
( x → y ) > ( y → x ) .This compound statement is defined as the conjunction of the two conditional statements .In these type of statements the first statement is known as hypothesis and statement y is known as the conclusion .In the second statement y is the hypothesis and x is the conclusion .

The above statements are described by the truth table as :
x    y  x->y   y->x   ( x → y ) > ( y → x )
T    T    T          T        T
T    F    F          T        F
F    T    T          F        F
F    F    T          T        T
When both the statements have the same truth values then the compound statement
( x → y ) > ( y → x ) is also true . So , this is the way of combine the two conditional statements and have a bi conditional . In the next topic we are going to discuss Boolean Laws and if anyone want to know about How to solve Perpendicular equations then they can refer to Internet and text books for understanding it more precisely.

Compound Statements

Previously we have discussed about math equation solver and Today I am going to discuss about the compound statements in discreet math( you can also try compound interest calculator) which is a part of maharashtra secondary and higher secondary education board. Compound Statements in mathematics is very interesting and easy to learn. As we know that compound means combining two or more parts as to form a mix, so here we will learn to make the compound statements and how to solve compound statements. To compose a compound statement there are various ways. For this we have many connectors such AND, OR, IF….THEN, NOT etc.

Instead of using a simple statement again and again we use a single letter which represent whole thing. For example: (want to Learn more about Compound Statements, click here),

Statement: “I have money.”
A : “I have money”.
 We can replace this statement by ‘A’. So we don’t need to use this statement again and again, instead of this we simply use ‘A’.

To construct Compound statements we use following connectors:
1.     NOT: This is known as negation. Example: "I am not busy" we can replace it with:
2.     AND: This is called conjunction.
 Example: Here A : “I am going to market”.
                                   B: “I am going to park”.

                       A>B: “I am going to market AND park”.

3.     OR: This is called disjunction.

Example: Here A: I will go to the market.

                        B: Amit will go to the park.

                        AVB: I will go to the market OR amit will go to the park.

4.     IF…. THEN: This is called Conditional.
Example: Here A: I want to buy cloths.
                                    B:I will go to the market.

A->B: If I want to buy cloths then I will goto market.

Now to understand the basic concepts let us take an example:
Given: p is true, q is false and r is true.
Now to determine truth value of this compound statement (
q ) ->r.

P	q	r		q	( q)->r
T	F	T	F	F	T

We construct a truth table for the given statement to determine truth value.
So here I explained about the Compound Statements and how to solve compound statements, next I will tell you about Bi Conditional Statements and if anyone want to know about Steps of Solving equations with decimals then they can refer to Internet and text books for understanding it more precisely.